Program For SJF (Preemptive)

#include <stdio.h>
int main()
{
int arrival_time[10], burst_time[10], temp[10];
int i, smallest, count = 0, time, limit;
double wait_time = 0, turnaround_time = 0, end;
float average_waiting_time, average_turnaround_time;
printf("\nEnter the Total Number of Processes:\t");
scanf("%d", &limit);
printf("\nEnter Details of %d Processes\n", limit);
for(i = 0; i < limit; i++)
{
printf("\nEnter Arrival Time:\t");
scanf("%d", &arrival_time[i]);
printf("Enter Burst Time:\t");
scanf("%d", &burst_time[i]);
temp[i] = burst_time[i];
}
burst_time[9] = 9999;
for(time = 0; count != limit; time++)
{
smallest = 9;
for(i = 0; i < limit; i++)
{
if(arrival_time[i] <= time && burst_time[i] < burst_time[smallest] && burst_time[i] > 0)
{
smallest = i;
}
}
burst_time[smallest]--;
if(burst_time[smallest] == 0)
{
count++;
end = time + 1;
wait_time = wait_time + end - arrival_time[smallest] - temp[smallest];
turnaround_time = turnaround_time + end - arrival_time[smallest];
}
}
average_waiting_time = wait_time / limit;
average_turnaround_time = turnaround_time / limit;
printf("\n\nAverage Waiting Time:\t%lf\n", average_waiting_time);
printf("Average Turnaround Time:\t%lf\n", average_turnaround_time);
return 0;
}

OUTPUT:

Enter Burst Time:
1:4
2:3
3:7
4:1
5:2

Process     Burst Time          Waiting Time    Turnaround Time
4                 1                 0                   1
5                 2                 1                   3
2                 3                 3                   6
1                 4                 6                   10
3                 7                 10                  17

Average Waiting Time=4.000000
Average Turnaround Time=7.400000