Parser: Use statement kind optional?

[joehoyle]

I see that Statement::Use is:

pub struct Use {
    pub name: SimpleIdentifier,
    pub alias: Option<SimpleIdentifier>,
    pub kind: Option<UseKind>,
}

kind is optional, whereby UseKind is Normal|Function|Const. Is it possible for UseKind to be None in that case? If so, what code would that look like? Sorry if that's a simple question!

[ryangjchandler]

This is a side effect of using the same Use structure inside of a regular UseStatement as well as a GroupUse.

Below shows all valid cases.

use Foo;               // kind: Some(Normal)
use const FOO;   // kind: Some(Const)
use function bar; // kind: Some(Function)
use Foo\{
	Bar,					// kind: None (should be inferred from GroupUse)
	function baz,	// kind: Some(Function)
	const QUX		// kind: Some(Constant)
};

I'm not against storing the kind against the Use in all-cases, it's just duplicate data since it's also stored at the GroupUseStatement level.