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modular abelian quotient -- something goes wrong #6392
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comment:1
G is strictly speaking not a subgroup of J[1] in this example it's a subgroup of J[0]. What happens if you travel down the code is equivalent to this:
Now the source code of _quotient_by_finite_subgroup is
So i guess it should instead return
There is also a problem with the is_subgroup code: Maybe I'm a bit confused but is the intersection of abelian varieties defined in an other way than just the set theoretic one. Because by reading the source code I really get the feeling that it does. The errors certainly seem to come from different assumtions about this in different parts of the code. |
comment:2
My confusion mainly comes from the following:
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Stopgaps: todo |
Branch: u/klui/finite_subgroup |
comment:9
The issue was in This branch returns the identity map as well when quotienting by a trivial group. New commits:
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Commit: |
comment:11
ok, let it be. Please add author full name. |
Reviewer: Frédéric Chapoton |
comment:13
Author name is missing.. |
Author: Kevin Lui |
Changed branch from u/klui/finite_subgroup to |
This isn't right:
This is
For some reason J[1]/G isn't even creating the right output (i.e., pair (abvar, map)).
CC: @koffie
Component: modular forms
Stopgaps: todo
Author: Kevin Lui
Branch/Commit:
0bc6f5a
Reviewer: Frédéric Chapoton
Issue created by migration from https://trac.sagemath.org/ticket/6392
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