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RemoveOuterMostParentheses.java
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RemoveOuterMostParentheses.java
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/*
Problem Statement:
A valid parentheses string is either empty (""), "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation. For example, "", "()", "(())()", and "(()(()))" are all valid parentheses strings.
A valid parentheses string S is primitive if it is nonempty, and there does not exist a way to split it into S = A+B, with A and B nonempty valid parentheses strings.
Given a valid parentheses string S, consider its primitive decomposition: S = P_1 + P_2 + ... + P_k, where P_i are primitive valid parentheses strings.
Return S after removing the outermost parentheses of every primitive string in the primitive decomposition of S.
Problem Link:
Remove Outermost Parentheses: https://leetcode.com/problems/remove-outermost-parentheses/
Solution:
https://github.com/sunnypatel165/leetcode-again/blob/master/solutions/RemoveOuterMostParentheses.java
Author:
Sunny Patel
https://github.com/sunnypatel165
https://www.linkedin.com/in/sunnypatel165/
*/
class Solution {
public String removeOuterParentheses(String S) {
return removeOuterParenthesesWithoutStack(S);
//return removeOuterParenthesesUsingStack(S);
}
public String removeOuterParenthesesWithoutStack(String S) {
StringBuilder answer = new StringBuilder();
int start =0, end=0,count=0;
while(start<S.length()){
count++; end++;
while(count!=0){
if(S.charAt(end)=='('){
count++;
answer.append("(");
} else {
count--;
if(count!=0)
answer.append(")");
}
end++;
}
start = end;
}
return answer.toString();
}
public String removeOuterParenthesesUsingStack(String S) {
Stack<Character> stack = new Stack<>();
StringBuilder answer = new StringBuilder();
int start =0, end=0;
while(start<S.length()){
stack.push(S.charAt(end++));
while(!stack.empty()){
if(S.charAt(end)=='('){
stack.push('(');
answer.append("(");
} else {
stack.pop();
if(!stack.empty())
answer.append(")");
}
end++;
}
start = end;
}
return answer.toString();
}
}