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Fix handling of unterminated bracket expressions in fnmatch (bug 28792)
When fnmatch processes a bracket expression, and eventually finds it to be unterminated, it should rescan it, treating the starting bracket as a normal character. That didn't happen when a matching character was found while scanning the bracket expression.
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/* Test for fnmatch handling of unterminated bracket expression (bug 28792) | ||
Copyright (C) 2022 Free Software Foundation, Inc. | ||
This file is part of the GNU C Library. | ||
The GNU C Library is free software; you can redistribute it and/or | ||
modify it under the terms of the GNU Lesser General Public | ||
License as published by the Free Software Foundation; either | ||
version 2.1 of the License, or (at your option) any later version. | ||
The GNU C Library is distributed in the hope that it will be useful, | ||
but WITHOUT ANY WARRANTY; without even the implied warranty of | ||
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU | ||
Lesser General Public License for more details. | ||
You should have received a copy of the GNU Lesser General Public | ||
License along with the GNU C Library; if not, see | ||
<https://www.gnu.org/licenses/>. */ | ||
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#include <fnmatch.h> | ||
#include <support/check.h> | ||
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static int | ||
do_test (void) | ||
{ | ||
/* An unterminated bracket expression should be rescanned, treating the | ||
open bracket as a normal character. The backslash causes the close | ||
bracket to be treated as a normal character, not ending the bracket | ||
expression. */ | ||
TEST_VERIFY (fnmatch ("[", "[", 0) == 0); | ||
TEST_VERIFY (fnmatch ("[[", "[[", 0) == 0); | ||
TEST_VERIFY (fnmatch ("[\\]", "[]", 0) == 0); | ||
TEST_VERIFY (fnmatch ("[[\\]", "[[]", 0) == 0); | ||
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return 0; | ||
} | ||
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#include <support/test-driver.c> |