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If we are expecting at least one element then we can do
if len(cc_version) == 2: ... else: ...
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Or:
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Ya something like this. I didn't have a computer at that moment, so couldn't express myself clearly. Sorry.
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o['variables']['gcc_version'] = 10 * cc_version[0]
This line always run, because
cc_version[0]
refers the major version of gcc.Now I think, we only need to check if
cc_version[1]
exists. If exists, use your value, if not exists show a warning message. Like the code above.I've used
try .. except
because Python encourages use oftry
.I've tested
if .. else
way and mytry ... except
way, both ways have solved this issue.There was a problem hiding this comment.
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I agree that Python encourages EAFP: Easier to ask for forgiveness than permission. But I wanted to make sure that the code is easily understandable. Anyway I am not going to hold this PR with this discussion. Please continue.
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Agreed. Will land as is.