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Move NameTuple method out of class #10282

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Aug 7, 2021
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1 change: 1 addition & 0 deletions news/10280.bugfix.rst
Original file line number Diff line number Diff line change
@@ -0,0 +1 @@
Fix 3.6.0 compatibility in link comparison logic.
52 changes: 26 additions & 26 deletions src/pip/_internal/models/link.py
Original file line number Diff line number Diff line change
Expand Up @@ -256,33 +256,33 @@ class _CleanResult(NamedTuple):
subdirectory: str
hashes: Dict[str, str]

@classmethod
def from_link(cls, link: Link) -> "_CleanResult":
parsed = link._parsed_url
netloc = parsed.netloc.rsplit("@", 1)[-1]
# According to RFC 8089, an empty host in file: means localhost.
if parsed.scheme == "file" and not netloc:
netloc = "localhost"
fragment = urllib.parse.parse_qs(parsed.fragment)
if "egg" in fragment:
logger.debug("Ignoring egg= fragment in %s", link)
try:
# If there are multiple subdirectory values, use the first one.
# This matches the behavior of Link.subdirectory_fragment.
subdirectory = fragment["subdirectory"][0]
except (IndexError, KeyError):
subdirectory = ""
# If there are multiple hash values under the same algorithm, use the
# first one. This matches the behavior of Link.hash_value.
hashes = {k: fragment[k][0] for k in _SUPPORTED_HASHES if k in fragment}
return cls(
parsed=parsed._replace(netloc=netloc, query="", fragment=""),
query=urllib.parse.parse_qs(parsed.query),
subdirectory=subdirectory,
hashes=hashes,
)

def _clean_link(link: Link) -> _CleanResult:
parsed = link._parsed_url
netloc = parsed.netloc.rsplit("@", 1)[-1]
# According to RFC 8089, an empty host in file: means localhost.
if parsed.scheme == "file" and not netloc:
netloc = "localhost"
fragment = urllib.parse.parse_qs(parsed.fragment)
if "egg" in fragment:
logger.debug("Ignoring egg= fragment in %s", link)
try:
# If there are multiple subdirectory values, use the first one.
# This matches the behavior of Link.subdirectory_fragment.
subdirectory = fragment["subdirectory"][0]
except (IndexError, KeyError):
subdirectory = ""
# If there are multiple hash values under the same algorithm, use the
# first one. This matches the behavior of Link.hash_value.
hashes = {k: fragment[k][0] for k in _SUPPORTED_HASHES if k in fragment}
return _CleanResult(
parsed=parsed._replace(netloc=netloc, query="", fragment=""),
query=urllib.parse.parse_qs(parsed.query),
subdirectory=subdirectory,
hashes=hashes,
)


@functools.lru_cache(maxsize=None)
def links_equivalent(link1: Link, link2: Link) -> bool:
return _CleanResult.from_link(link1) == _CleanResult.from_link(link2)
return _clean_link(link1) == _clean_link(link2)