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Remove MacCall special cases from Parser::parse_full_stmt
It is impossible for expr here to be a braced macro call. Expr comes from `parse_stmt_without_recovery`, in which macro calls are parsed by `parse_stmt_mac`. See this part: let kind = if (style == MacStmtStyle::Braces && self.token != token::Dot && self.token != token::Question) || self.token == token::Semi || self.token == token::Eof { StmtKind::MacCall(P(MacCallStmt { mac, style, attrs, tokens: None })) } else { // Since none of the above applied, this is an expression statement macro. let e = self.mk_expr(lo.to(hi), ExprKind::MacCall(mac)); let e = self.maybe_recover_from_bad_qpath(e)?; let e = self.parse_expr_dot_or_call_with(e, lo, attrs)?; let e = self.parse_expr_assoc_with( 0, LhsExpr::AlreadyParsed { expr: e, starts_statement: false }, )?; StmtKind::Expr(e) }; A braced macro call at the head of a statement is always either extended into ExprKind::Field / MethodCall / Await / Try / Binary, or else returned as StmtKind::MacCall. We can never get a StmtKind::Expr containing ExprKind::MacCall containing brace delimiter.
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