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Don't recursively expand undefined macros #12197
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,20 @@ | ||
// Copyright 2014 The Rust Project Developers. See the COPYRIGHT | ||
// file at the top-level directory of this distribution and at | ||
// http://rust-lang.org/COPYRIGHT. | ||
// | ||
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or | ||
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license | ||
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your | ||
// option. This file may not be copied, modified, or distributed | ||
// except according to those terms. | ||
|
||
fn main() { | ||
print!(test!()); | ||
//~^ ERROR: macro undefined: 'test' | ||
//~^^ ERROR: macro undefined: 'test' | ||
//~^^^ ERROR: format argument must be a string literal | ||
|
||
concat!(test!()); | ||
//~^ ERROR: macro undefined: 'test' | ||
//~^^ ERROR: expected a literal | ||
} |
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Why would this print the error twice?
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I didn't actually quite figure that out. This has to do with constructing a nested parser that doesn't have the same macro context as the outer context, but at least one of the errors is for the sub-parser complaining about an unknown macro, and the second error message may come from the original parser parsing the expression again?
I figured going from infinity instances of 'macro undefined' to two was at least somewhat better. Fixing the two prints I think would require a better understanding of macro parsing (which may be a reason to reject this patch).
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The double error occurs because of how format_args!() is defined. If the first argument is not a string literal then it emits an error but also expands to the first argument. So then the macro is attempted to be expanded again, and fails.